FOUR DIGIT NUMBERS ARE FORMED USING THE DIGITS 1,2,3,4,5[REPETITIONS AMONG THESE DIGITS ALLOWED].THE NUMBER =>?

THE REQUIRED NUMBERS ARE:

1111 1122 1133 1144 1221 1232 1243 1331 1342 1441 [1O]

2112 2123 2134 2211 2222 2233 2244 2321 2332

2342 2431 2442 2344 [12]

3113 3124 3212 3223 3234 3311 3322 3344 3421

3432 3443 [11]

4114 4213 4224 4323 4334 4411 4422 4433 4444 [9]

THUS TOTAL NUMBER IS 42

NONE OF ANSWES GIVEN IS CORRECT.

HENCE,THE REQUIRED CLUE IS E.NONE OF THESE

I wrote a simple computer program that went thru all 5^4 possible numbers and counted the ones that were divisible by 11 and got 85 so the answer would be E

For a number to be divisible by 11.

Sum of odd place numbers = sum of even place numbers

As repetition is allowed in this case,

1111 will be the first number and 5555 will be the last number.

So sum of odd place numbers or even place numbers ranges from 2 (in 1111) to 10 (in 5555).

No. of numbers with sum 2 = 1

No. of numbers with sum 3 = 4

Possible with digits 1 and 2

Numbers like 1122, 1221 , 2112, 2211.

So 4 numbers.

No. of numbers with sum 4 = 9

Possible with (2,2) and (1,3)

With (2,2) = 1 only ( 2222)

With (1,3) = 4 ( like in previous case)

With (1,3) and (2,2) = 4 ( 1232, 3212, 2123, 2321)

No.of numbers with sum 5 = 16

Possible with (1,4), (2,3) and (1,4,2,3).

Now it follows a pattern.

LIke 1, 4, 9, 16, 25, 16, 9, 4, 1

So Answer = 1+4+9+16+25+16+9+4+1

= 85

Answer is E NONE OF THESE

a) Are you really going to type all your maths homework into here without understanding IT'S YOUR HOMEWORK - a test of your understnding, not ours!

b) Why do you keep shouting?

Go ask your Maths teacher!

e

E NONE OF THESE

BORING !!!! Thanks for the points though !