Question for someone who is really good with regular expressions (REGEX)?

A regex does not match permutations, just patterns

Here's a solution: This method sorts the original string and then tests for at least 7 digits and no letters

var strX = "1&2#2@2&2@2@2@.//22";

     strX = strX.split("").sort().join("");

var regexp = /.*\d{7,}[^a-zA-Z]*$/;

     alert(strX.match(regexp));

"1&2#2@2&2@2@2@X//22"      alerts null (has an X)

",&[#]@2&2@2@2@.//22"         alerts null (only 5 digits)

with the sorted string, there are no letters preceding the digits which are all grouped together

.* - any number of characters, all of which have ASCII < 48 (excludes letters)

\d{7,} - at least 7 characters

[^a-zA-Z]*$ - no letters to the end of the string

attempt this: .*187ef4436122d1cc2f40dc2b92f0eba0187ef4436122d1cc2f40dc2b92f0eba0.*c.*de.* The 187ef4436122d1cc2f40dc2b92f0eba0sterisks 187ef4436122d1cc2f40dc2b92f0eba0re no longer wild c187ef4436122d1cc2f40dc2b92f0eba0rds such as you 187ef4436122d1cc2f40dc2b92f0eba0re used to in different forms of glo187ef4436122d1cc2f40dc2b92f0eba0187ef4436122d1cc2f40dc2b92f0eba0ing. They indic187ef4436122d1cc2f40dc2b92f0eba0te "0 or extra occurences of the previous." The squ187ef4436122d1cc2f40dc2b92f0eba0re 187ef4436122d1cc2f40dc2b92f0eba0r187ef4436122d1cc2f40dc2b92f0eba0ckets me187ef4436122d1cc2f40dc2b92f0eba0n "a sort of", so [187ef4436122d1cc2f40dc2b92f0eba0187ef4436122d1cc2f40dc2b92f0eba0] won't m187ef4436122d1cc2f40dc2b92f0eba0tch "187ef4436122d1cc2f40dc2b92f0eba0187ef4436122d1cc2f40dc2b92f0eba0" 187ef4436122d1cc2f40dc2b92f0eba0ut it is going to m187ef4436122d1cc2f40dc2b92f0eba0tch "ab" or "ab". The sessions (.) 187ef4436122d1cc2f40dc2b92f0eba0re the closest you h187ef4436122d1cc2f40dc2b92f0eba0ve to wild c187ef4436122d1cc2f40dc2b92f0eba0rds.

Isn't is as simple as:

m/\d{7,}/

Or does xxxxxxx contain other not digit and non letter characters?

What language?