Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Need some extra help on rational exponents...?
I've tried to solve these two problems over 20 times now and I cannot figure out my mistake. I'm not one to just ask my homework questions on line because I'm lazy - I tried for these, I swear!
1) (8a^-6)^-2/3
2) (9n^-5)^-3/2
I know that the answer to 1 is supposed to be (a^4)/4. I've gotten the answer 4/(a^4) but do not see which inverse I am messing up to get to the real answer.
Thanks for your time, Nathan S.
2 Answers
- Anonymous1 decade agoFavorite Answer
1.(8/a^6)^-2/3
(cube root)(8/a^6)^-2
(cube root)(a^12/64)
a^4/4
2. (9n^-5)^-3/2
(9/n^5)^-3/2
√(9/n^5)^-3
√(n^15/729)
n^7√n/27
- 1 decade ago
hello, dear.
okay, for the first one, separate each term & work them individually:
(8) ^ -2/3 & (a ^ -6) ^ -2/3
for the (a ^ -6) ^ -2/3 you just multiply the exponents, or powers together to get an answer of:
a ^ 4
& for the 8 ^ -2/3, just take it to the denominator to make the exponent positive:
a ^ 4
-------
8 ^ 2/3
a ^ 4
--------
4
for the second problem, repeat the same exact steps.
hope this helps! good luck!
Source(s): 99% in AP calculus. ; ]