algebra question ,can u solve by method?

let the present ages be

x for A

y for B

so x + y = 28.............(1)

now when A was of B's age that is (x -y) years ago

the ages would be

for A x - (x - y)

= y (obviously)

for B y - (x - y)

= 2y - x

now acc. to ques

y = 5 ( 2y - x)

y = 10y - 5x

5x - 9y = 0

x = 9y/5..............................(2)

putting values of x in (1)

9y/5 + y = 28

14y/5 = 28

y = 10

and also x = 28-10 =18

there fore A's present age is 18 years

and of B is 10 years

i hope, now you got the full solution

A=5B

A+B=28

A=28-B

A=A so...

5B=28-B

6B=28

B=28/6

A= (28/6)*5=140/6

Convert to Years and Months:

A=140/6 = 23 Years, 4 Months

B=28/6 = 4 Years, 8 Months

What!??? if i understood correctly you asked what is "a" and "b"

in a + b=28

5b=a

if that is right then you simply subtract b from the first equation to make it a=28-b, then you put both equations together like this --> 28-b=5b (because both equations are equal to a)

then you add b to both sides to make it 28=6b (5b + 1b = 6b)

then you divide both sides by 6 and get b=4.6666....

which is 4yrs 8 months

then you plug in 4.666... in to one of the original equations and get a=23.3333...

Let A be x yrs and B be y yrs (present)

x+y=28

y=28-x

A was of B's age (x-y) yrs ago

y=5(x-y)

y=5x-5y

6y=5x

6(28-x)=5x

168-6x=5x

168=11x

x=

Sorry im lost..i tried ver hard though..

"When I was your age, I was 5 times old as you were"

That makes NO sense...