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Chess
Chess asked in Science & MathematicsMathematics · 1 decade ago

How do I evaluate this indefinite integral?

∫[cos(pi/x)]/x^2 dx

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  • Anonymous
    1 decade ago
    Favorite Answer

    Try using u-substitution with u=pi/x.

    Source(s): BS in math
  • Anonymous
    1 decade ago

    ∫ cos(π/x) / x² dx

    −sin(π/x) / π + C

    Its obvious when you realize that the denominator (treated as a multiple) is the derivative of whats inside to cosine function.

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