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What should I let u be in evaluating this indefinite integral?
∫[sinx]/[(cosx)^2 + 1]
1 Answer
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- jeredwmLv 61 decade agoFavorite Answer
The natural choice is u = cosx. This nicely kills off the sinx in the numerator (it is absorbed into du), and the integral becomes
- ∫ 1 / (u²+1) du.
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