Algebra I question for brother. HELP!! EASY!!!?

Example 7:

Find the slope and the y-intercept of the line y = -2.

Note how we do not have an x. This type of linear equation was shown in Tutorial 14: Graphing Linear Equations. When we have y = c, where c is a constant, then this graph is what type of line?

If you said horizontal, you are correct.

Since this is a special type of linear equation that can’t be written in the slope/intercept form, I’m going to give you a visual of what is happening and then from that let’s see if we can’t figure out the slope and y-intercept.

The graph would look like this:

(go to website)

(horizontal line)

The slope equals 0.

Now let’s look at the y-intercept. Looking at the graph, you can see that this graph crosses the y-axis at (0, -2). So the y-intercept is (0, -2).

The slope is 0 and the y-intercept is -2.

So I guess you answer would be y = -8

If it has no slope then it would just be a straight line. So I guess the answer would be the y=-8?

-8=(0)(6) + b

-8=0+b

-8=b

y=-8

Because there is no slope, the line is staright across, always equalling -8 or (0,-8).

y=-8

slope intercept form - y = mx + b

m = slope

b = y intercept

for this; y = 0x - 8

y = mx + b

m = 0

y = (0)x + b

y = b

The line is horizontal.

You know it goes through y = -8. The x's don't matter, since, being horizontal, it goes through all x's.

Therefore: y = -8.

its a straight line

y= -8