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Please help with statistics?
16 ft length of chain has an average of 2650 lbs and a standard deviation of 520 lbs. If a retailer receives an order of 75 chains, what is the probability that the sample mean will be greater than 2800 lbs?
1 Answer
- Ja MaLv 51 decade agoFavorite Answer
2800-2650 = 150 lbs
sample size = 75
square root of sample size = 8.66
standard deviation of the distribution of sample means = 520/8.66 = 60
150/60 = 2.5 std devs
from microsoft excel normdist(2.5) = 0.99379
probability that the sample mean will be less than 2800 = 99.379%
probability that it will be greater than 2800 = 100 - 99.379 = 0.621%