Math help? Standard from, slope, stuff like that?

1. Put equation in y=mx+b form. The "m" is the slope!

5y=20-4x

2. Divide each term by 5 to get y by itself.

y=4-4/5x (I like to rewrite it as y=-4/5x+4)

3. The "m" in y=mx+b form is before the x. Look at y=-4/5x+4.

The m (slope) is before the x. So what's the slope?!

-4/5! <- Ta da!

Hope this helped! (:

First the easy way, if you have standard form like you wrote Ax+By=C, the slope is always -A/B.

Secondly, you want to end up with y=mx+b (m=slope, b=y-intercept). Step 1: subtract 4x from each side: 5y=-4x+20

Step 2: isolate y by dividing by 5. y=(-4/5)x+20

So, m=slope=(-4/5) and the y-intercept is 4

subtract over 4x --> 5y = -4x + 20

divide by 5-----------> y= -4/5 x + 4

Slope = -4/5

Y-int = 4