if xsquared +8x+c is a perfect square trinomial, what is the value of c?

c = 16

x^2 + 8x + 16

(x+4) ^2

c is 16

(x+a)^2 = x^2 + 2ax + b^2

x^2 + 8x + c is perfect square trinomial

so we can write, x^2 + 2* 1* 4x + 4^2

so c = 16

SO x squared+8x+c=perfect quare trinomial

Xsquare+8x=perfect square trinomial - c

8xsquared=perfect square trinomial - c (whatever this is suppose to be)

8Xsquared divided by perfect square trinomial - c (whatever this is suppose to be)

SO after you should be getting 16

Good Luck

(x + a)^2 = x^2 + 2a x + a^2

x^2+8x+c

8 = 2a : a = 4 so c = a^2 = 16

16

half of B squared...