Need Help with Math Please?

When asked to solve for y, that means to put it in slope intercept form, y=mx+b, where m is the slope and b is the y intercept:

10x+5y= -25 subtract 10x from each side:

5y= -10x-25 divide by 5:

y= -2x-5

Find the slope and y intercept of 25x+5y=15 exactly the same as the first question, exactly the same steps, so I'll leave it to you to do.

Write in standard form: (-2,-3) m=4. Standard form is ax+by=c basically. So the first thing you need to do is find the y intercept, which is NOT the same as the b in the standard form. I know, but I didn't make it up, I'm just explaining it. So first, to find the y intercept, use the coordinates and the slope in the slope intercept form y=mx+b and solve for b (the y intercept b):

y=mx+b, m=4, (-2,-3)

-3=-2(4)+b multiply

-3=-8+b add 8 to both sides

5=b so the y intercept is 5, your line equation is:

y=4x+5, and to put it in standard form, subtract 4x from each side:

-4x+y=5 and since you don't want to lead with a negative number, multiply everything by -1:

4x-y= -5.

wpf.

1. 10x + 5y= -25

To solve for y, isolate y (put it on one side of the equation).

10x + 5y= -25

5y = -10x - 25

y = -2x - 5

2. 25x + 5y = 15

5y = -25x + 15

y = -5x + 3

The slope is -5. The y-intercept is 3.

3. Standard form of an equation: Ax + By = C.

First, in y = mx + b form:

y = mx + b

Substitute any known values.

-3 = 4(-2) + b

Solve for b.

-3 = -8 +b

-3 + 8 = b

5 = b

The equation of the line in slope y-intercept form is y = 4x + 5.

Therefore, the equation in standard form is 4x - y = -5.

no of unknowns>no of equations

so infinite sol

y=2x-5 x may take any value.

1) 25x+5y=15

i.e, y=-5x+3

slope= -5 and y-intercept is 3

2) Y+3=(X+2)4