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Volume/Integral Calculus Question?
The volume of a cell increases at a rate of 100/(1 + t)^2 cubic micrometres/s. If the cell is initially 500 cubic micrometres in volume, find its ultimate size after a long period of time.
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- rozeta53Lv 61 decade agoFavorite Answer
dV/dt=100/(1 + t)^2
dV=100*dt/(1 + t)^2
V(t)=∫100*dt/(1 + t)^2=-100/(1+t)+C
t=0 ==> V(0)=500=-100+C ==> C=600
V(t)=600-100/(1+t)
t=∞ ==> V(∞)=600 cubic micrometres
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