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Can anyone solve this differential equations problem?
Solve the following by the method of seperation of variables:
3x''=5t Initial conditions- x(0)=2 x'(0)=7
That's x double prime in the problem
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- ?Lv 71 decade agoFavorite Answer
3x''=5t
x''= 5t/3
x' = 5/3 (t^2/2) + c1 = 5/6 t^2 + c1
x'(0) = c1 = 7
x(t) = 5/6 (t^3/3) + 7t +c2
x(t) = 5/18 (t^3) + 7t +c2
x(0) = c2 = 2
so x(t) = 5/18 (t^3) + 7t + 2
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