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Paul caught exactly 3 times as many fish as Eric and exactly 4 times as many as Steve. If they caught..?
less that 100 fish altogether, what is the greatest number of fish that Paul could've caught?
-72
-66
-60
-50
-48
4 Answers
- 1 decade agoFavorite Answer
P=3E
P=4S
Answer 1:
Paul=72
72=3E
E=24
72=4S
S=18
72+24+18=114, so NO
Answer 2:
Paul=66
66=3E
E=22
66=4S
S=16.5
Since you can't catch 16.5 fish, 66 is WRONG
Answer 3:
Paul=60
60=3E
E=20
60=4S
S=15
60+20+15=95 (less than 100)
The Answer is 60
- Jerome JLv 71 decade ago
P + E + S < 100
P + P/3 + P/4 < 100
12P + 4P + 3P < 1200
19P < 1200
P < 1200/19
P < 63.15
The greatest integer divisible by 3 and 4 but less than 63 is 60.
So the answer is 60.
- 1 decade ago
The answer is 60.
Source(s): By expressing quantities of Eric and steve in terms of Pauls catch we can express the total as [ 19 P < 12 x 100 ] . Solving this for maximum value of P as a whole number gives the answer Paul( 60 )+ Eric (20) + Steve (15) = 95 For values higher than 60 for Paul, the total would exceed 100 - Anonymous1 decade ago
50.
