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Water flowing through a hole (finding flow rate and speed at which water level drops) help!?
A 4.0mm diameter hole is 1.0m below the surface of a 2.0m diameter tank of water. A) What is the volume flow rate throught the whole in L/min? B) What is the rate in mm/min at which the water level in the tank will drop if the water is not replenished?
15 hours ago - 3 days left to answer.
1 Answer
- kirchweyLv 71 decade agoFavorite Answer
A. Bernoulli's principle says energy density of a liquid (J/m^3) = pressure + ρgh + ρv^2/2. (See ref.; ρ is density.) Conservation of energy means if you reduce one of them (e.g., h), another of them (e.g., v) increases. Thus exit velocity v = sqrt(2gh). Volume flow rate Q = v*hole area. If this is all computed in MKS, the result so far is Q in m^3/s. To scale to ltr/min, multiply by 1000*60. With this information you can solve B. Just keep your work in meters (h, area, volume, flow rate, etc.), and finally convert your answer to the units the question wants.
