Solve using the quadratic formula:x2 – 3x – 3 = 5?

x² - 3x - 8 = 0

3±√41

------- = x

..2....

x = 1.5 ± √10.25

Hi ,

I think you the formula and you shall get the answer.Let's try to derive an formula for a general quadratic terms .

Let us take a quadratic equation ax^2+bx+c = 0

Now we have to derive the value of "x".

If p*q = 0 then we get EITHER p = 0 OR q = 0.

So if I get in terms of p,q we get our answer.So let us try.

------> Multiply by 4a on both sides we get (2ax)^2+2(2ax)(b)+4ac = 0.

------->Now let us try to get in the formula of (a+b)^2.Addind and subtracting b^2 on the left hand side we get

(2ax)^2+2(2ax)(b)+b^2--b^2+4ac = 0

--------> Now I write the first three terms as ( 2ax+b)^2 and take "--" common in the second so I get a formula of p^2--q^2 that can be written in the form of (p+q)(p--q)

---------> ( 2ax+b)^2--{sqrt(b^2--4ac)}^2 = 0

---------> {2ax+b+sqrt(b^2--4ac)} {2ax+b--sqrt(b^2--4ac)} = 0

----------> x = [--b+(or)--{sqrt(b^2--4ac)}]/2a

NOTE:This formula is applicable whan quadratic equation is in standard form.

Now let us solve your problem taking a = 1 b = --3 c = --8 (By transforming 5 on the other side)

Apply the above formula x = [--(--3)+(or)--{sqrt((--3)^2--4(1)(--8)}]/2(1)

By solving you get x = [3+(or)--sqrt41]/2

ANSWER: x = [3+(or)--sqrt41]/2

x² - 3x - 8 = 0

x = [ 3 ± √ (9 + 32 ) ] / 2

x = [ 3 ± √ 41 ] / 2

x2-3x-3=5

x2-3x=5+3

x2-3x=8

x(2-3)=8

x(-1)=8

x=8/(-1)

x= -8

Very simple and accurate answer

x2-3x-3=5 subsituing x=(-8)

(-8)2 - 3(-8)-3=5

-16+24-3=5

8-3=5

5=5

get everything one one side so it reads x2-3x-8 = 0

a represents coefficient of sqaured term, b rep. coeff. of x and c is just -8. It's just plug and chug it aint that hard.

dwefwf