Simple C program Help computer programming C?

If your friend says he knows C++, but not C, he doesn't know C++. C++ is a superset of C

See below for my translation of this code into C. Notice how my sscanf statement provides input validation and allows some flexibility in the input format. Also notice how I've moved all variable declarations before the statements. Traditional C doesn't allow inline declarations as C++ does.

#include <stdio.h>

#include <math.h>

#define MAX_STR_LEN 1024

int main (int argc, char *argvp[]) {

    char line[MAX_STR_LEN];

    int A1, A2, A3, B1, B2, B3;

    double A2X, B3X, X, Y, ans;

    do {

        printf("\nEnter integers A1,A2,A3,B1,B2,B3 : ");

        fgets(line,MAX_STR_LEN,stdin);

    } while (sscanf(line, "%d ,%d ,%d ,%d ,%d ,%d",

                    &A1,&A2,&A3,&B1,&B2,&B3) != 6);

    A2X = sqrt(pow((double)A2,2)/2);

    B3X = sqrt(pow((double)B3,2)/2);

    X = A1 + A3 + B2 + A2X + B3X;

    Y = A2X + B3X;

    X = pow(X, 2);

    Y = pow(Y, 2);

    ans = sqrt(X + Y);

    printf("\nThe answer is: %g\n", ans);

    return 0;

}

Sample run:

Enter integers A1,A2,A3,B1,B2,B3 : 1,2,3

Enter integers A1,A2,A3,B1,B2,B3 : 1 , 2,3 ,4 , 5, 6

The answer is: 15.7106

There is no cin or cout in C.

Use scanf() and printf() respectively.

Now, when using scanf, you need an extra method to allow it to take in any string.

Also, keep in mind that there are no actual strings in C. In C, strings are just arrays of chars that end in a null or 0 char (not '0', ASCII value of 0).

Also, there is no std:: stuff, cut that all out (As far as I know, I mean, there may be some third pary stuff, or something...) Anyway, yeah, just use include. There are good examples online, everywhere. Just look on Google, google knows all.

the following code would work, #include <stdio.h> #include <conio.h> void main() { clrscr(); printf("\n hello"); getch(); } the reason why your program did give the expected output is that you didn't use "getch();" in your code. when you give this getch(); then only when you press any key, you can come out of the console window, where as if you don't give it, without showing you the required output, the control returns back to the program. so it is wrong to say that the program didn't generate the output, which means the program had given the required output but that is not visible. so try the above code and see. i hope this would have cleared your doubt. "ALL THE BEST FOR YOUR STUDIES"

Be sure it is in correct syntax, a lot can go wrong or not work at all if part of the script isn't typed correctly as a command.

It compiles and runs correctly for me under Cygwin on Windows, but %d should be %f in the printf().

Everything looks correct to me. convert it to C, and test it.