help with physics hw?

Question

At 6 seconds after 3:00, a butterfly is observed leaving a flower whose location is  (6,-3, 10) m relative to an origin on top of a nearby tree. The Butterfly flies until 10 seconds after 3:00, when it alights on a different flower whose location is (6.8,-4.2,11.2)m relative to the Origin. What was the location of the butterfly at a time 8.5 seconds after 3:00? What assumption did you have to make calculation this location? 

How do you do that? Do you use instantaneous velocity? If so, how do you find it?

Anonymous · Accepted Answer

I'm not 100% on this but I would find the average distance traveled in each direction over those 4 seconds so .8, -1.2, and 1.2 meters in the 4 seconds which means when you're looking for 8.5 seconds after 3:00 it would be 2.5 seconds after he started moving.  

2.5/4 * . 8 = .5 
2.5/4 * -1.2 = -.75
2.5/4 *. 1.2 = .75

Position assuming the butterfly traveled in a straight line and at a constant velocity would be (6+.5, -3 + -.75, 10 + .75)  or (6.5, -3.75, 10.75)

schihl · Answer

Acceleration = tension / mass. speed = acceleration * time. potential = tension * speed #a million assume uniform tension at each and each section. in the blocks, the acceleration = 5/0.2 = 20m/s² tension = 20*70 = a million,400N Out of the blocks, acceleration = (12-5)/5 = 7/5m/s² tension = 7/5*70 = 98N user-friendly potential = ninety 8*(12+5)/2 = 833W #2 Conservation of potential. assume gravity = 10 m/s² (you need to use 9.80 one in case you like and you have a calculator) potential potential at 100m relative to the floor = 10 * a hundred * 3 = 3,000J potential potential at 50m = a million,500J Kinetic potential at 50m = a million,500J you may calculate its velocity from this: 31.6 m/s

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help with physics hw?

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