help me solve my math plss!!?

(4x/3)-2(x+1)=(x/2) multiply by (2*3) on each side to get rid of fractions

8x - 12(x+1) = 3x

8x-12x-12= 3x

-4x-12=3x

-12=7x

x= -12/7

(4x/3) -2(x +1) = (x/2)...

Multiply both sides with 6 (3 * 2.. the two denominators in the question)

6*(4x/3) - 6*2(x +1) = 6x/2 that is

8x - 12x - 12 = 3x, and this is

-4x -12 = 3x, and this is

7x = -12

x = -12/7

Multiply both sides by 6 to get rid of fractions.

6[(4x/3)-2(x+1)]=(x/2)(6)

8x-12(x+1)=3x, now distribute the 12 and solve for x

8x-12x-12=3x

-7x-12=0

x=-12/7

1. FOIL to -2(x+1) to -2x-2

2. Find a common denominator for all the fractions (6 works)

8x-12x-12=3x

3.Then solve for x:

-4x-12=3x

-7x=12

x= -1.71

First, u multiply everything by 6 to get

8x-12(x+1)=3x

8x-12x-12 =3x

-4x-(3x) -12=3x- (3x)

-7x=12

x= - 12/7

x = -12/7

(8x/3) -4(x+1) = x

8x/3 - x -4(x+1) = 0

5x/3 -4x - 4 = 0

5x/3 - 4x = 4

5x - 12x = 12

-7x = 12

x = -12/7

a million) you want to locate one hundred * (#blue lead pens/ finished pens) observe, the one hundred merely makes it a proportion cost i.e. => .15(one hundred) = 15% So, If there are Z pens finished and S are purple then (Z-S) is the style of Blue pens. answer: a) one hundred*[(Z-S)/Z) = [one hundred (Z – S) ] / Z 2) For this one all of us understand that (pi) is continuous so area purely transformations with exchange in radius (r) So, if we put in attempt values. R=a million and 3 R^2 = a million and 9 OR R=2 and 6 R^2 = 4 and 36 the two way the area of the circle Y is 9 circumstances greater than X for all valuable values of X. answer: e) not one of the above

4x/3 - 2x - 2 = x/2

4x/3 - 2x - x/2 = 2

8x/6 - 12x/6 - 3x/6 = 2

-7x/6 = 2

7x = 12

x= 12/7

(4/3)x - 2x - 2 - .5x = 0

(-7/6)x = 2

x = -12/7

(4x/2) -2x -2 = x/2

time by 2

4x-4x-4=x

therefore x = -4