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Polar Coordinates – Equation of Locus of Points?
A line segment of length 2a slides with its ends on the x and y-axes. Find the polar equation of the locus described by the point P(r, θ) at which the perpendicular from the origin intersects the moving line.
That's r = a sin(2θ).
I can see by carefully plotting points that the answer apperas to be asin(2θ), but I am interested in how to derive the answer.
1 Answer
- nleLv 71 decade agoFavorite Answer
r* ( tan(theta) + cot(theta) ) =2a
or
r= 2 a/ ( tan(theta) + cot(theta) )
EDIT : proof is easy
call the line AB
AP =OP tan(theta)
BP = OP cot(theta)
add
AP + BP= OP (tan(theta) +cot(theta) )
2a = r ( tan(theta) +cot(theta) )
which is reduced to your equation