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Allele frequencey of a PHENOTYPE?
"In a certain population, the dominat PHENOTYPE (not genotype) of a certain trait occurs 91% of the time. What is the frequancey of the dominant allele?"
2 Answers
- Asst ProfLv 71 decade agoFavorite Answer
The frequency of the dominant allele is 0.7, and it is done this way:
The frequency of the recessive phenotype (let's call it rr) is 1-0.91= 0.9.
Therefore, the frequency of the recessive allele, r, is sqrt 0.09=0.3.
So, the frequency of the dominant allele, R, is 1-0.3 = 0.7.
- 1 decade ago
91% = AA and Aa
therefore 9% = aa
1 = p^2 + 2pq + q^2 (hardy weinberg)
p = dominant allele, A
q = recessive allele, a
p^2 + 2pq = 0.91
q^2 = 0.09 therefore q = 0.3 or 30% frequency of recessive allele (a)
total of p + q must equal 1 since there is only two alleles so if the frequency of a is 30% the frequency of A must be 70%
