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Reducing rational expressions?
How would I do this
75xy^2 z^7 / 45x^4 y^3 z^6
8 Answers
- Engr. RonaldLv 71 decade agoFavorite Answer
75xy^2z^7
-----------------
45x^4y^3z^6
....5z
=------------- answer//
...3x^3y
- Anonymous1 decade ago
The original expression=
(75/45)[x^(1-4)][y^(2-3)][z^(7-6)]=
5z/(3yx^3)
- ?Lv 45 years ago
the reason being x^0 = a million (something to the capacity 0 is a million) least puzzling thank you to try this branch is to subtract the exponent values interior the denominator from the value interior the numerator for an identical base. We get x^(5-2)y^(3-3)z^(2-7) = x^3y^0z^-5 that's comparable to x^3/y^5
- An ESL LearnerLv 71 decade ago
(75xy^2z^7)/(45x^4y^3z^6)
= (75/45)(x/x^4)(y^2/y^3)(z^7/z^6)
= (5/3)(1/x^3)(1/y)(z)
= 5z/(3x^3y)
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- 1 decade ago
75 on top, 45 on bottom --> 5/3
x on top, x^4 on bottom --> x^3 on the bottom
y^2 on top, y^3 on bottom --> y on the bottom
z^7 on top, z^6 on bottom --> z on top
