plss solve and give me a solution?

Given 5y - 7 + y = 7y + 21 - 5y

Combine like terms

6y - 7 = 2y + 21

Subtract 2y from both sides

4y - 7 = 21

Add 7 to both sides

4y = 28

Divide both sides by 4

y = 7

Check: Substitute 7 in the place of y

5 • 7 - 7 + 7 = 7 • 7 + 21 - 5 • 7

35 - 7 + 7 = 49 + 21 - 35

35 = 70 - 35

35 = 35

ANSWER: y = 7

y=7

5y-7+y=7y+21-5y

add 7 to both sides

5y+y=7y+28-5y

add 5y and y

6y=7y+28-5y

add 5y to both sides

11y=7y+28

subtract 7y from both sides

4y=28

28 divided by 4 is 7

y=7

you already know, this is no longer lots help whilst people try this for you, however the subject to undergo in suggestions is write down what you already know. call Rita's age "X", her son's age "Y". Now, write down what you already know. She grow to be 35 whilst her son grow to be born, so HIS age, Y, is 25 below hers. So, Y= X - 25 you already know that their a while upload as much as a hundred and five, so, X + Y = a hundred and five. Now, you already know, from the 1st equation, that Y = X -25, so, in the 2nd equation, you are able to replace the "Y" with "(X - 25)", precise? So, the 2nd eqation will become X + X - 25 = a hundred and five Now, upload 25 to the two aspects to get rid of that " - 25" challenge and X + X = a hundred thirty, or 2X = a hundred thirty Divie the two aspects by employing 2 X = sixty 5 X - 25 = 40

5y - 7 + y = 7y + 21 - 5y .add y's on each side

6y - 7 = 2y + 21..............subtract 2y from each side

4y - 7 = 21.....................add 7 to both sides

4y = 28..........................divide both sides by 7

y = 4

5(7)-7+7=7(7)+21-5(7)

35-0=49+21-35

35 = 35

so y=7

5y-7+y=7y+21-5y

6y-7=2y+21

6y-2y=21+7

4y=28

y=7

this would be

(7y+21-5y)-(5y-7+y)=0

2y+28-6y=0

2y-6y=-28

-4y=-28

y=-28/-4

y=7

check:

5y-7+y=7y+21-5y

5(7)-7+7=7(7)+21-5(7)

35=49+21-35

35=70-35

35=35

:)

easy: )

No solution.

no i'm sorry i'm really good in math you just didnt explain it to me good enuff:)