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Car and stopping power?
if a car is traviling at 60 mph with a weight of 1500kg and the brake is applied at with the force of 10N how far does it take for the car to stop when friction is not an issue? or when friction is an issue?
Sorry i just relized, when friction is not an issue, the car will not stop because there will be no friction created between the brake and the wheel of the car.
1 Answer
- Doctor QLv 61 decade agoFavorite Answer
60 mph = 26.8167 ms^-1
10 = 1500 * a
a = 6.66*10^-3 (this is the deceleration)
Now....
v = u + at
0 = 26.8167 + -6.66*10^-3 * t
-26.8167 = -6.66*10^-3 * t
time = 4026.53 seconds
Now.....
s = ut + 1/2 at^2
s = 28.8167 * 4026.53 + 1/2 * 6.66^-3 * 4026.53^2
s = 116031.35 + 53989.10 = 170020.45 metres or 170.02 kilometers
A very very long long way to stop eh!!!
