x^2-18=0 can someone explain step by step how to solve this problem.?

x^2-18=0

x^2=18

x=±√18

x=±√(9*2)

x=±3√2

x=3√2, -3√2 answer//

x^2-18=0

x^2=18

x=sqrt of 18

x^2-18=0

x^2=18

x=sqrt of 18

x^2 -18 = 0

We want to isolate the x, so we move the -18 over to the right.

so x^2 = 18.

We want to find x, and since x^2 = 18,

we sqrt(18)

x= ±sqrt(18) = ± 4.243

Anything squared(whether positive or negative) gives a positive value

x^2-18=0

x^2-18+18=0+18

x^2=18

Square root of x=square root of 18

x(which is square root of x^2)=whatever the square root of 18 is

What os the problem? To solve? x = rt18. Just take 18 on the RHS and find the sq root.

x^2 - 18 = 0

Add 18 to both sides of the equation.

x^2 = 18

Take the root of both sides.

x = (sqrt)18

or

x = (sqrt)9 * (sqrt)2

or

x = 3(sqrt)2

(a+b)(a-b) =a^2 -b^2

x^2 -18=0

(x-sqrt18)(x+sqrt18)=0

x=sqrt 18 or -sqrt18

x= 3sqrt2 or -3sqrt2