Probability Question...?

the cumulative distribution function of a uniformly distributed variable on the [0,1] interval is:

F(x) = P(X≤x) = 0 if x≤0

F(x) = x if 0≤x≤1

F(x) = 1 if x≥1

since A,B,C are independent, the cumulative distribution function Fabc(x,y,z) of A, B and C is the product of the separate cumulative distribution functions of A, B and C.

In other words,

Fabc(x,y,z) = Fa(x)Fb(y)Fc(z)

Fabc(x,y,z) = 0 if x≤0 or y≤0 or z≤0

Fabc(x,y,z) = xyz if 0≤x≤1, 0≤y≤1 and 0≤z≤1

Fabc(x,y,z) = xy if 0≤x≤1, 0≤y≤1 and z≥1

Fabc(x,y,z) = xz if 0≤x≤1, 0≤z≤1 and y≥1

Fabc(x,y,z) = zy if 0≤z≤1, 0≤y≤1 and x≥1

Fabc(x,y,z) = x if 0≤x≤1, y≥1 and z≥1

Fabc(x,y,z) = y if 0≤y≤1, x≥1 and z≥1

Fabc(x,y,z) = z if 0≤z≤1, y≥1 and x≥1

Fabc(x,y,z) = 1 if x≥1, y≥1 and z≥1