Problems of Ions in Aqueous Solutions and Colligative Properties?

5) ΔTf = Kf * m *i

where Kf is a constant , m is the molality , i is the number of particles in solution in this case =1

for water Kf = 1.86

so 25 = 1.86 *m *1

m = 13.44

6) Kf for Acetic acid = 3.90

ΔTf = Kf * m *i

1.3 = 3.9 * m * 1 ; so m = .333

m= .333 moles / Kg of solvent = .06666 moles in 200 ml

= .06666 * 32.04 g of methanol = 2.12 g

7) Kf for water = 1.86

ΔTf = Kf * m *i

.34 = 1.86 * m *1

m= .182m

I hope the "solutions" are helpful P:

Dont have plenty time will answer ebe07b5ab71cb128f4b7addf2aa48cdst one. Freezing pt melancholy is: ?Tf = Kf - m for this reason 7.ebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cd= Kf-m m is gram solute consistent with kg solvent is [ebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cdebe07b5ab71cb128f4b7addf2aa48cd]ebe07b5ab71cb128f4b7addf2aa48cd0.5 you be conscious of Kf from tables and now locate X.