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find the value of x (10 points)?
the perimeter = 36
its a rectangle
the width is 2
and the length is squareroot (x+7)
5 Answers
- shinsplints99Lv 71 decade agoFavorite Answer
p = perimeter
w = width
l = length
p = 2w + 2l
p = 36
w = 2
l = sqrt(x + 7)
36 = 2(2) + 2sqrt(x + 7)
36 = 4 + 2sqrt(x + 7)
Subtract 4 from both sides:
32 = 2sqrt(x + 7)
Divide both sides by 2:
16 = sqrt(x + 7)
Square both sides:
256 = x + 7
Subtract 7 from both sides:
249 = x
x = 249
- 1 decade ago
x=249.
Here are the basic steps:
36= 2+2+Squareroot (x+7)+ Squareroot (x+7)
36=4+ (2 times the Squareroot (x+7))
32=2*Squareroot (x+7)
16=Squareroot (x+7)
256= x+7
249=x
Hope this helps!
- a_ebnlhaithamLv 61 decade ago
Width + length = 18
So length = 16
16 = sqrt (x+7) squaring both sides
256 = x + 7
x = 249
- 1 decade ago
2+2+(2 times sqrt(x+7))=36
4+2(sqrt(x+7)=36
2(sqrt(x+7)=32
sqrt(x+7)=16
x+7=16 times 16
x+7=256
x=249
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