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3x^2+8x-3=0 complete the square?
10 points
8 Answers
- MimiLv 41 decade agoFavorite Answer
x= 1/3 , -3
1)divide out by 3 on both sides to set the leading coeff. to 1
3x²+8x-3=0
---------------
3
= x²+8/3x-1=0
2)Add 1 to both sides
x²+8/3x-1=0
+1 +1
=x²+8/3x=1
3)Figure the following on the side:
b=8/3
½b=4/3
(½b)²=16/9
4) use the results to complete the square by adding 16/9 to both sides.
x²+8/3x = 1
+16/9 +16/9
=x²+8/3x +16/9 = 25/9
5) convert the new polynomial back to an equal squared binomial.
x²+8/3x +16/9 = 25/9
(x+4/3)² =25/9
6)take the square root of both sides. (dont for get the plus minus on the answer side!)
√ (x+4/3)² =±√ 25/9
simplify.
x+4/3 = ± 5/3
7)solve for both x's
x+4/3 = 5/3
-4/3
x=1/3
x+4/3 = - 5/3
-4/3
x=-3
- Anonymous4 years ago
a million) x^2+8x= -15 then you definitely could discover: (b/2)^2 using fact the answer to this formulation will supply you the variety that makes a suitable sq. trinomial. (8/2)^2= sixteen then: you may upload sixteen to the two facets. x^2+8x+sixteen= -15+sixteen this is now straight forward to element the suitable sq. trinomial. (x+4)^2= a million with the intention to isolate the x, you may choose to first sq. root the a million which delivers: x+4= +/-a million subtract 4 from the two facets for the two suggestions: x= -a million-4= -5 x= a million-4= -3 this is the variety you finished the sq.. the tactic the guy above me used became factorizing. i do no longer choose to remedy the rest for you using fact i could be depriving you of getting to know the thank you to get the solutions your self.
- a_ebnlhaithamLv 61 decade ago
3x^2+8x-3 = 3 ( x^2 + 8/3 x + 16/9) - 16/3 - 3
= 3 ( x + 4/3)^2 - 25/3 = 0
So (x + 4/3)^2 = 25/9
So (x + 4/3) = (+/-) (5/3)
either x = 5/3 - 4/3 = 1/3
or x = 5/3 + 4/3 = 9/3 = 3
- 1 decade ago
ax^2+bx+c=0
divide by 3
x^2 + (8/3)x -1 =0
add (b/2)^2 in both sides
x^2+(8/3)x-1+ (16/9) - (16/9)=0
(x+16/9)^2-25/9=0
.....
OR from begaining
(3x-1)(x+3)=0
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- Anonymous1 decade ago
3x^2+8x-3=0
(3x-1)(x+3)=0
x= 1/3 or -3
- 1 decade ago
3x^2 - 9x + x - 3 = 0
3x(x - 3) + 1(x - 3) = 0
(3x + 1)(x - 3) = 0
3x/3 = -1/3
x = -1/3 or x = 3