please help me in math thanks!!!?

A^X=b

X=lnb/lnA

If you meant 2x/(3 - 1) = 7/x 2x/(3 - 1) = 7/x 2x×x = 7×2 2x^2 = 14 x^2 = 7 x = ±√7 so x = 2.64575 or -2.64575 Or did u mean 2x/3 - 1 = 7/x 2x/3 - 1 = 7/x x(2x/3 - 1) = 7 2x^2/3 - x = 7 x^2 - 3x/2 = 21/2 (x - 3/4)^2 = 21/2 + 9/16 (x - 3/4)^2 = 168/16 + 9/16 (x - 3/4)^2 = 17716 x - 3/4 = ±√(177/16) x = 3/4 ± √(177/16) so x = 4.07603 or -2.57603 Hope this helps you. *βω*

1. Take log on both sides; log4^x=log17

This equates to xlog4=log17

This means x=log17/log4

Calculate log 17 and log 4 to get the answer (you can use your calculator for this)

2. Take log on both sides

log.e^-0.8t=log0.90

-0.8tloge=log0.90

t=log0.90/loge.(-0.8)

Remember, loge=1

t=log0.90/(-0.8)

calculate log0.90 (you can use your calculator for this)and get value of t

3. take log on both sides giving you

log3.3^x=log76; this means

xlog3.3=log76

x=log76/log3.3

Calculate log76 and log 3.3 to get the value of x (you can use your calculator for this)

take log/ln both sides and you get the ans

4^x=17

xln4 = ln17

x = ln17/ln4

do the same for the next 2 questions

These problems are pretty basic.

x = log(17)/log(4)

-.8t = ln(.9)

t = -ln(.9)/.8

x = log(76)/log(3.3)

Take out your calculator, and enter carefully. Pay attention to parentheses.

1) 4.25

i jus done random numbers

i dnt no number 2 or 3 sorry

im only 13 but my math level is 12th grade so i think on da 1st one u have to subtract 4 on each side or sumthing like dat

1. you just have to find what power of 4 will get you to 17. its between ^2 or ^3

(do that for 3 too)

idk how to solve the 2nd one

Use a scientific calculator that can do logs, this isn't possible in-your-head or by hand.

you need to eat more rats to get your brain going boy, these are easy questions even I can do. But I won't do for you because you won't give me rats.