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Sliding down ramp with kinetic friction?
A 44.9-kg seal at an amusement park slides from rest down a ramp into the pool below. The top of the ramp is 1.80 m higher than the surface of the water and the ramp is inclined at an angle of 33.9° above the horizontal. If the seal reaches the water with a speed of 4.51 m/s, what is the work done by kinetic friction?
Also, What is the coefficient of kinetic friction between the seal and the ramp?
3 Answers
- feanorLv 71 decade agoFavorite Answer
v = sqrt (2gh) = 5.94 m/s is the speed without friction so the difference is the frictional loss
0.5 m (v1^2 - v2^2) = 336.2 J = Fd
F = 336.2/(1.8/sin 33.9) = 104.2 N
Fn = 44.9 * 9.81 * cos 33.9 = 365.6
u = F / Fn = 0.285
- knrLv 61 decade ago
1)work done by kinetic friction = P.E of seal - K.E of seal
= mgh - 1/2 m v^2 , using the values and solving we can get work done = 335.401 J
2) velocity down the ramp is v = square root of [ 2gL( sin(theta) - u cos (theta)]
= square root of [2gh( 1 - u cot (theta) ]
where 'u' is the coefficient of friction
using the values and simplifying we can get,
coefficient of friction u = 0.2846 ( v = 4.51m/s given )
- ?Lv 44 years ago
if we are able to advance ramp attitude? weight? decrease friction? then making maximum of gravity will paintings ultimate. it extremely is going to additionally rely on length of ramp.very short will choose a mild weight low friction motor vehicle. long ( er) reward extra style greater weigh making maximum of gravity allure down ramp. returned low friction rolling skill is considerable key.