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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

About word problems! Specifically, distance problems?

Cynthia runs an average of 8.33 m/s while Alberta has an average speed of 10 m/s. If the faster runner accomplishes the race 2 seconds ahead of the slower runner, what is the total distance of the race?

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  • 1 decade ago
    Favorite Answer

    Speed=Distance/Time

    Therefore, Distance=Speed x Time

    Cynthia

    Time=x

    Speed=8.33m/s

    Distance=8.33 x Time

    =8.33x

    Alberta

    Time=x-2 ( because she finished the race 2 seconds faster)

    Speed=10m/s

    Distance=10(x-2)

    Since both cover equal distances

    8.33x=10(x-2)

    Solving for x we get

    x=20/1.67 seconds

    Therefore distance will be :8.33 x 20/1.67=99.76047904191617

  • 1 decade ago

    If 't' is the time taken by Alberta to run the distance, then t+2 is the time taken by Cynthia. But both have travelled same distance. Therefore

    8.33*(t+2) = 10*t

    or t = 8.33*2/(10-8.33)

    There for distance = 10 * 8.33 * 2/ (10 - 8.33)

  • 1 decade ago

    x = distance

    Cynthia: x = 8.33t

    Alberta is 2 seconds ahead thus if she runs the same distance her formula looks like: x = 10 (t-2)

    8.33t = 10 (t-2) =>

    t = 11.98 s

    x = 8.33*11.98 = 99.8 m

  • Anonymous
    5 years ago

    Perimeter: P = 2W + 2L You know the perimeter (500) and the width (104), so you can easily solve for the missing dimension 500 = 2(104) + 2L

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  • 1 decade ago

    Sofia is correct. I get 99.7605 m

  • Anonymous
    1 decade ago

    10k i think

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