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About word problems! Specifically, distance problems?
Cynthia runs an average of 8.33 m/s while Alberta has an average speed of 10 m/s. If the faster runner accomplishes the race 2 seconds ahead of the slower runner, what is the total distance of the race?
6 Answers
- 1 decade agoFavorite Answer
Speed=Distance/Time
Therefore, Distance=Speed x Time
Cynthia
Time=x
Speed=8.33m/s
Distance=8.33 x Time
=8.33x
Alberta
Time=x-2 ( because she finished the race 2 seconds faster)
Speed=10m/s
Distance=10(x-2)
Since both cover equal distances
8.33x=10(x-2)
Solving for x we get
x=20/1.67 seconds
Therefore distance will be :8.33 x 20/1.67=99.76047904191617
- 1 decade ago
If 't' is the time taken by Alberta to run the distance, then t+2 is the time taken by Cynthia. But both have travelled same distance. Therefore
8.33*(t+2) = 10*t
or t = 8.33*2/(10-8.33)
There for distance = 10 * 8.33 * 2/ (10 - 8.33)
- 1 decade ago
x = distance
Cynthia: x = 8.33t
Alberta is 2 seconds ahead thus if she runs the same distance her formula looks like: x = 10 (t-2)
8.33t = 10 (t-2) =>
t = 11.98 s
x = 8.33*11.98 = 99.8 m
- Anonymous5 years ago
Perimeter: P = 2W + 2L You know the perimeter (500) and the width (104), so you can easily solve for the missing dimension 500 = 2(104) + 2L
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- Anonymous1 decade ago
10k i think