How do I solve the following equations?

2(3x + 1) - 3 = 6x - 1

6x + 2 = 6x - 1 + 3

0 = 2 - 2

0 = 0

Answer: There is no definite solution to this problem—its number of solutions is infinite. Any value you'll assign to x will work:

Example (x = 0):

2(3[0] + 1) - 3 = 6(0) - 1

2(0 + 1) - 3 = 0 - 1

2(1) - 3 = - 1

2 - 3 = - 1

- 1 = - 1

Example (x = 7):

2(3[7] + 1) - 3 = 6(7) - 1

2(21 + 1) - 3 = 42 - 1

2(22) - 3 = 41

44 - 3 = 41

41 = 41

Example (x = - 7):

2(3[- 7] + 1) - 3 = 6(- 7) - 1

2(- 21 + 1) - 3 = - 42 - 1

2(- 20) - 3 = - 43

- 40 - 3 = - 43

- 43 = - 43

This is an incorrect Question. It has no answer.

2*3x+2*1-3=6x-1

6x+2-3=6x-1

2-3+1=6x-6x

-1+1=0

0=0

2(3x + 1) - 3 = 6x -1

Multiply out the bracket

6x+2-3=6x-1

6x-1=6x-1

Without a different equation this cannot be solved.

its just pemdas :D

so multiply the 2 into the brackets

2(3x+1) turns into :

6x+2

6x+2-3=6x -1

so it looks like

6x-1= 6x-1

o wow its solved

x= all real numbers enjoy

step 1: turn computer on, log into yahoo answers

step 2: type the question out and post

step 3: wait until some bored mathematics head sees the question

your welcome, i hope this helped

This question is impossible to solve because you need a second equation.