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Can someone tell me how to solve these math problems please?

4x+5x=63

70= 10(3t-2)

5y-(2y-10)

2(t-5)-3(2t+7)= 12-5(3t+1)

Update:

I wrote the third problem wrong. It's 5y-(2y-10)=25. Thanks Janda.

3 Answers

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  • Janda
    Lv 4
    1 decade ago
    Favorite Answer

    4x + 5x = 63

    4x + 5x = 9x

    So 63 = 9x.

    Divide both sides by 9.

    63/9=7

    x = 7

    Proof:

    4x7 + 5x7 = 28 + 35 = 63

    70 = 10 (3t-2)

    Divide both sides by 10.

    7 = 3t-2

    Add 2 to both sides.

    9 = 3t

    Divide both sides by 3.

    3 = t

    Proof: 70 = 10((3x3)-2) = 70 = 10(9-2) = 70 = 10x7

    Not sure if you wrote the 3rd one right.

    2(t-5)-3(2t+7) = 12-5(3t+1)

    Um, sorry can't do this one!

  • 1 decade ago

    Combine like terms (x's with x's), and distribute where there's a number multiplied by something in parentheses. You have to distribute the minus sign in the second one too. You want to get the variable alone (if there's an equal sign), always keep that in mind as your main objective. Remember that whatever you do, you have to do it to both sides.

    9x=63

    x=7

    70=30t-20

    90=30t

    3=t

    5y-2y+10

    3y-10

    2t-10-6t-14=12-15t-5

    -4t-24=7-15t

    24=7-11t

    17=-11t

    t= -11/17

  • Anonymous
    1 decade ago

    Yes, I can tell you how... the first step is to take each problem step by step and properly working through the problem yourself.

    I guess there are no other steps in this math tutorial, but I hope that helps!

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