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Can someone tell me how to solve these math problems please?
4x+5x=63
70= 10(3t-2)
5y-(2y-10)
2(t-5)-3(2t+7)= 12-5(3t+1)
I wrote the third problem wrong. It's 5y-(2y-10)=25. Thanks Janda.
3 Answers
- JandaLv 41 decade agoFavorite Answer
4x + 5x = 63
4x + 5x = 9x
So 63 = 9x.
Divide both sides by 9.
63/9=7
x = 7
Proof:
4x7 + 5x7 = 28 + 35 = 63
70 = 10 (3t-2)
Divide both sides by 10.
7 = 3t-2
Add 2 to both sides.
9 = 3t
Divide both sides by 3.
3 = t
Proof: 70 = 10((3x3)-2) = 70 = 10(9-2) = 70 = 10x7
Not sure if you wrote the 3rd one right.
2(t-5)-3(2t+7) = 12-5(3t+1)
Um, sorry can't do this one!
- joanna jLv 41 decade ago
Combine like terms (x's with x's), and distribute where there's a number multiplied by something in parentheses. You have to distribute the minus sign in the second one too. You want to get the variable alone (if there's an equal sign), always keep that in mind as your main objective. Remember that whatever you do, you have to do it to both sides.
9x=63
x=7
70=30t-20
90=30t
3=t
5y-2y+10
3y-10
2t-10-6t-14=12-15t-5
-4t-24=7-15t
24=7-11t
17=-11t
t= -11/17
- Anonymous1 decade ago
Yes, I can tell you how... the first step is to take each problem step by step and properly working through the problem yourself.
I guess there are no other steps in this math tutorial, but I hope that helps!