what's the solution for this inequalities witrh fraction and 2 variable?algebra help?

5/x + 2/y = 0

5y + 2x = 0

y = 2x/5

6/x + 4/y = 3

6y + 4x = 3xy

6y - 3xy = - 4x

y(6 - 3x) = - 4x

y = - 4x/(6 - 3x)

Value of x:

2x(6 - 3x) = 5(- 4x)

12x - 6x² = - 20x

6x - 3x² = - 10x

3x² = 16x

x = 16/3

Value of y:

= (2[16/3])/5

= 32/15

Answer: x = 16/3, y = 32/15

Check:

6/(16/3) + 4/(32/15) = 3

6(3/16) + 4(15/32) = 3

1.125 + 1.875 = 3

3 = 3

1B. -6 < 2x + 2 < 8 -6 - 2 < 2x < 8 - 2 -8 < 2x < 6 -4 < x < 3 2nd. the 2nd equation is 0.5 the 1st equation, so it does no longer supply us any new suggestion. as a result there are infinity strategies. 3-D. Double the 1st equation: 6x + 4y = 18 Triple the 2nd equation: 6x + 9y = 18 Subtract those very final 2 equations: 5y = 0 y = 0

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