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Who knows how to set these math problems up?
A candy mixture of 25% chocolate has been requested for an office reception. Mixtures of 50% chocolate or 10% chocolate are available. How much of each type should be mixed to get a 20 lb. mixture that is 25% chocolate?
Monica makes a $9.25 purchase at the bookstore with a $20 bill. The store has no bills and gives her the change in quarters and fifty-cent pieces. There are 30 coins in all. How many of each kind are there?
Can you answer this question too please?
1 Answer
- mohanrao dLv 71 decade agoFavorite Answer
let 50% chacolate = x lbs
Since total amount is 20 lb,
10% chacolate = 20 - x lb
so x(50/100) + (20 - x)(10/100) = 20(25/100)
50x + 200 - 10x = 500
40x = 300
x = 300/40
= 7.5 lb
so 50% chacolate = 7.5 lb
10% chacolate = 20 - 7.5 = 12.5 lb
b)
The balance amount = 20.00 - 9.25
= 10.75
let 25 cents coins = a
then 50 cents coins = 30 - a
so 25a + (30 - a)50 = 1075
25a + 1500 - 50a = 1075
25a = 425
a = 425 /25 = 17
25 cents (quarters ) = 17
50 cents coins = 30 - 17 = 13
