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Tossing a Coin and Binomial Distribution?
What is the probability of getting a second head on the 4th
trial of 5 independent trials of tossing a fair coin?
Please, show the work....like the distribution it uses.
Thanks!
1 Answer
- PopeLv 71 decade agoFavorite Answer
If you get the second head on the fourth toss, then you must get exactly one head in the first three tosses, and the fourth toss must fall heads.
P(1 head in 3 tosses) = C(3,1)(1/2)²(1/2) = 3/8
P(heads on the fourth toss) = 1/2
P(second head on fourth toss) = (3/8)(1/2) = 3/16
The fifth toss has no influence on this outcome.