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Algebra Help! Perimeter of a rectangle?
If a rectangle has a length of 2x-1 and a width of 8-2x what would the value of x have to be to make the rectangle a square?
4 Answers
- JacintaLv 71 decade agoFavorite Answer
The length would have to equal the width.
2x – 1 = 8 – 2x
2x = 9 – 2x
4x = 9
x = 9/4 (or 2¼)
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- 1 decade ago
to be a square then the length and width have to be the same so set it up like 2x-1 = 8-2x
flip the 8-2x to -2x+8
2x-1 = -2x+8
subtact both sides by 2x and get
-1= -4x+8
subtract 8 from both sides
-9= -4x
divide both sides by -4
and x= 9/4
