Please help me solve: x=(√5x-6)?

square both sides and it will end up like:

x^2 = (5x-6)

If you square both sides, you get, x^2 = 5x - 6.

Then rearrange this to give x^2 - 5x + 6 =0

This factorizes to give (x-3)(x-2) = 0

and so for this to be true, either of the brackets above must be zero,

Hence (x-3) = 0 and x=3

or (x-2) =0 and x = 2

and so the result is x =2 and x = 3

If you substitue these values in, you can see that these are the correct solutions

If 5x - 6 is all under the root sign (which is not clear from your post), then simply square both sides.

x^2 = 5x - 6

Then x^2 - 5x + 6 = 0 . Then factor and solve.

( )( ) = 0

etc.

you need the x's on one side, and the -6 on the other, so i THINK you can just put it like this (6=*squareroot*5x-x)...

you should define it more clearly i where does the square start and end.

i got it like that: x = (sqrt(5x)-6)

in this case it would be easy, just type into a calculator