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Poisson distribution?

Let X have a poisson distribution such that 3P( x =1) = P( x=2) find P( X =4)

Update:

Tried that I get something around 22 which makes no sense.

1 Answer

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  • efqy
    Lv 7
    1 decade ago
    Favorite Answer

    Write the formula for the Poisson probability function at x with parameter say lambda (or mu, or whatever symbol you wish for the parameter)

    What is P(X=2)? (it will be a function of lambda)

    What is P(X=1)? What is 3P(X=1)?

    Equate the two, cancel out common terms, you get a quadratic for the parameter. Now substitute that into the p.f. to evaluate P(X=4)

    --

    22 is completely wrong

    To save typing, I'll write in terms of the parameter mu

    P(X=x) = exp(-mu) mu^x/x!

    3P(X=1) = 3exp(-mu).mu

    P(X=2) = exp(-mu).mu^2/2

    exp(-mu).mu^2/2 = 3exp(-mu).mu

    mu^2/2 = 3.mu

    mu = 6

    That was what I said to do - what was hard about that?

    NOW evaluate P(X=4)

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