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how do I prove limits using epsilon delta in complex variables?
show that limit as z approaches i of the following function
2[(z^2-iz+2)/(z+3i)]= -i
1 Answer
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- Anonymous1 decade agoFavorite Answer
substitue in i for z
=2[(i^2-ii+2)/(i+3i)]
=2[(-1+1+2)/(4i)]
=2[2/4i]
= 1/i
= -i
No real need to do a full "limit" type calc, denominator does not approach 0.
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