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how do I prove limits using epsilon delta in complex variables?

show that limit as z approaches i of the following function

2[(z^2-iz+2)/(z+3i)]= -i

1 Answer

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  • Anonymous
    1 decade ago
    Favorite Answer

    substitue in i for z

    =2[(i^2-ii+2)/(i+3i)]

    =2[(-1+1+2)/(4i)]

    =2[2/4i]

    = 1/i

    = -i

    No real need to do a full "limit" type calc, denominator does not approach 0.

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