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In how many different ways can a panel of 12 jurors and 2 alternates be chosen from a group of 22 prospective?
WIll choose BEST answer and explanation
3 Answers
- M3Lv 71 decade agoFavorite Answer
the alternates are usually chosen specifically as alternates though they may or may not be told that they are alternates at the start
[see source cited]
based on this way of selection,
# of ways = 22C12*10C2 = 29 099 070 ways
[ you may note that 22C2*20C12 will give the same result ! ]
ans: 29 099 070 ways
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- louttitLv 44 years ago
Your questioning is optimal for the suggestions on a thank you to fill your 14 chairs. Are you inclusive of the branch via 12! to account for the numerous orders wherein the 12 that are chosen get referred to as? you in addition to mght would desire to divide the two alternates via 2! for the same reason.
- VFBundyLv 61 decade ago
22c14 = 22!/(14!*8!) = 319,770
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