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..:::Confused!:::... Will pick B.E.S.T answer :)?
A student planning her curriculum for the upcoming year must select one of five business courses, one of four mathematics courses, two of nine elective courses, and either one of four history courses or one of two social science courses. How many different curricula are available for her consideration?
If you could explain how to do this I'd greatly appreciate it
2 Answers
- ?Lv 71 decade agoFavorite Answer
There are 5 choices for the first course, 4 for the second, 9C2 = 36 for the third, and 6 (four history and two social science) for the last. By the multiplication rule, the total is:
5 * 4 * 36 * 6
EDIT: Jmann, no, there are not 9 * 8 = 72 ways to pick two electives. Order does not matter, so it is 9 * 8 / 2 = 36.
- 1 decade ago
If you are asking the number of different curricula available it is 5+4+9+1+2=21. but something tells me you are not...
If I remember my stats correctly this fits under the Fundamental Counting Principle. of the first five, any one can match up with any of the second four: 5*4. Then you have to pick two electives, first there will be nine available, then eight available after you take one course: 5*4*9*8. finally you have to choose from history or S-science, 4+2=6. 5*4*9*8*6=8,640. That is how many curricula variations she can take. But in reality, half the classes won't be taught this term and the other half filled to capacity or will be taught at the same time as another class she must take...
