anyone good at solving inequalities?

the little line means less than or equal to

-3 + x <= 0

x <= 3 (add three to both sides)

solution set is { x| x <= 3 }

Okay, first, to solve the inequality, you can do anything to an equation or inequality as long as you do it to both sides (meaning the left and right of the < symbol). You want to get it so that only X is on the left and everything else is on the right. If you add 3 on the left side, all that remains is the X, so do that and then also add 3 to the right side:

-3 + X < 0, add 3 to both sides

(+3) - 3 + X < 0 (+ 3), add +3 and -3 on the left to get 0. Add 0 + 3 to get 3 on the right

0 + X < 3, the zero doesn't matter so you get

X < 3, this says "X is less than 3". If you have < with a line, that means "X is less than or equal to 3".

The solution set is all of the numbers that X can equal (so every number that is either 3 or lower than 3). So you write

{x| x < 3} But use the < with the line. This gets read as "X is the set of all values where X is less than or equal to 3".

- 3 + x < 0

Treat this like a regular equation and solve for x.

-3 + x < 0

Add 3 to both sides.

x < 3

This answer means that in order to satisfy the original inequality, the values for x must be less than 3 or else you will make a false statement for the inequality.

PROVE:

Say x = 2

-3 + x < 0

-3 + 2 < 0

-1 < 0....This is a true statement because -1 is smaller than 0.

What about if x = 5?

-3 + x < 0

-3 + 5 < 0

2 < 0....This is false because 0 is NOT bigger than 2.

Understand?

The solution set is written {x|x < 3}....This is read: "x such that x is less than three."

the line under the < makes the inequality read "minus three plus x is less than or equal to zero."

to solve, add 3 to both sides, then you have: x< or = 3

To graph that solution, draw a line on the x axis from 3 to positive infinity, with a coloured in circle at 3.

The solution set is {x| x<=3}

In our school we solve it like this...

-3+x< 0

+x<0 over - 3

and the solution is done ...inequalities are way easy.

PS: There's a little line because I think it shows the signs or something, I don't remember it clearly it was ages ago..

The little bar implies "equal to". So it you add 3 to both sides you get

x< or equal to (the little bar under it) 3

The solution set is {x: x< or equal to 3}

To graph it draw a number line. (Just a straight line with evenly spaced markings between each number.) Then you just put a dot on 3 and and arrow that goes to the left. This indicates that x and be anything on that line that is to the left of (less than) 3.

I hope this helps!

X < 3 plus the line goes there. Add 3 to both sides its basic algebra. if 0 is more then x -3 then if you change both sides equaly the relationship remains the same so X is less then or equal to 3

solution set is x <3 which means 3<x<negative infinity

ie x I[ 3<X< -INFINITY ]

THE SOLUTION ABOVE IS WRONG BECAUSE X CAN TAKE ANY VALUE BETWEEN 3 AND NEGATIVE INFINITY.

x=>-1