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Eric
Lv 6
Eric asked in Science & MathematicsPhysics · 1 decade ago

Help calculating the capacitance per meter of a cable?

Question:

A coaxial cable used in a transmission line has an inner radius of 0.10mm and an outer radius of 0.60mm. Calculate the capacitance per meter for the cable. Assume that the space between the conductors is filled with polystyrene. (Also assume that the outer conductor is infinitesimally thin).

Polystyrene dielectric constant : κ=2.6

Now the book says the answer is 81 pF/m; however, I have no idea how to reach this conclusion. I have a feeling it has something to do with:

C= ε₀A/d

Help would be much appreciated. Thanks for your time!

2 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    First you need to calculate the capacitance for a cylindrical capacitor, not parallel plates (the formula you listed). Look at a cross section of the wire so that you see a ring representing the outer radius surrounding a solid circle representing the inner radius of the wire. Then draw a gaussian surface in the empty space between the two pieces of wire and apply Gauss' law.

    First: E = electric field at a radial distance R. The wire has length L.

    q = ε₀EA = ε₀E(2πRL) where 2πRL is the area of the curved part of the Gaussian surface. Solve this equation for E = q / (2πε₀LR)

    Then, you need to take the integral of E from the outer radius to the inner radius along a radial path. This gives you the potential difference between the two pieces of wire.

    V = int(E, ds) = -q/(2πε₀L) int(dr/r) where the bounds of integration are a and b, the inner and outer radii. The integral of 1/r is ln(r), subtituting your bounds in you get ln(b/a).

    Then, C = q/V

    C = 2πε₀L / ln(b/a)

    Drop the term L to find the capacitance per unit length.

    edit: I assumed no dielectric in this whole derivation, you simply multiply it into the numerator of the above equation.

  • Anonymous
    4 years ago

    Cable Capacitance Calculator

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