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Please help with physics?
Starting from rest, a basketball rolls from the top of a hill to the bottom, reaching a translational speed of 6.6m/s. Ignore frictional losses. a) whst is the height of the hill? b) released from rest at the same height, a can of frozen huice rolls to the bottom of the same hill. What is the translational speed of the forzen juice can when it reaches the bottom?
1 Answer
- 1 decade agoFavorite Answer
Apply the law of conservation of energy:
Energy at Top = Energy at Bottom
At the top, the ball only has potential energy. At the bottom, the ball has both rotational and linear kinetic energy.
mgh = ½mv² + ½Iω²
For pure roll, ω = v/r.
I, the moment of inertial can be looked up in a table. It will be a multiple of mr², so r will cancel out.
Solving for h:
h = (mv² + Iω²)/(2mg)
Solving for v:
sqrt[2gh - Iω²/m] = v
