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Probability. I'm stuck :( .. Will choose BEST answer?
Data compiled by the Department of Justice on the number of people arrested in a certain year or serious crimes (murder, rape, robbery, and so on) revealed that 89% were male and 11% were female. Of the males, 30% were under 18, whereas 27% of the females arrested were under 18.
A) What is the probability that a person arrested for serious crime in that year was under 18?
B) If a person arrested for a serious crime in that year is known to be under 18, what is the probability that the person is female?
1 Answer
- M3Lv 71 decade agoFavorite Answer
qA
P[male <18 & arrested] = 89% x 30% = 2670/10^4
P[female <18 & arrested] = 11% x 27% = 297/10^4
P[<18 & arrested] = sum of the above = 2967/10^4
= 0.2967
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qB
P[ female | <18 & arrested] = P[female <18 & arrested] /P[<18 & arrested]
= 297/2967
= 0.1001
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