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-==Probability question. Will choose the BEST answer!!==-?
In a study of the scientific research on soft drinks, juices, and milk, 50 studies were fully sponsored by the food industry, and 30 studies were conducted with no corporate ties. Of those that were fully sponsored by the food industry, 14% of the participants found the products unfavorable, 23% were neutral, and 63% found the products favorable. Of those that had no industry funding, 38% found the products unfavorable, 15% were neutral, and 47% found the products favorable
1. What is the probability that a participant selected at random found the products favorable?
2. If a participant selected at random found the product favorable, what is the probability that he or she belongs to a group that participated in the corporate-sponsored study?
1 Answer
- M3Lv 71 decade agoFavorite Answer
S = sponsored
F = favorable
q1
P[ S & F ] = [50/80]*0.63 = 0.3938
P[ S ' & F ] = [30/80]*0.47 = 0.1763
P[ F ] = sum of the above = 0.5701
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q2
P[ F | S ] = P[ S & F ] / P[ F ]
= 0.3938/0.5701
= 0.6908
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