Chemistry question related to the Mole Concept, please help?

Balanced equation:

Mg(OH)2 + 2HCl → MgCl2 + 2H2O

1mol Mg(OH)2 reacts with 2mol HCl

Check for limiting reactant:

Molar mass Mg(OH)2 = 58.3198 g/mol

203g = 203/58.3198= 3.48mol Mg(OH)2

This will require 6.96mol HCl

Molar mass HCl = 36.453

Mol HCl = 164/36.453 = 4.499mol HCl available

You have insufficient HCl, which is the limiting reagent: Concentrate onl on HCl and MgCl2

2mol HCl will produce 1mol MgCl2

4.499mol HCl will produce 4.499/2 = 2.25mol MgCl2

Molar mass MgCl2 = 95.2115 g/mol

2.25mol MgCl2 = 2.25*95.2115 = 214.2g MgCl2

Answer: You can produce 214.2g MgCl2

firstly you find which of the reactents are in excess by writing an equation and calculating the mole of each reactent,

Mg(OH)2 + 2HCL ---> MgCl2 + 2H2O

n(Mg(OH)2) = (mass of reactant) / (molar mass) = 203/ (24.3+32+2) = 3.5 mol

n(HCL) = 164/36.5 = 4.5

since Mg(OH)2 to HCL is a 1:2 ration, the HCL is the limiting reactant, thus you can use the mole ration in the equation to find how many mole of MgCl2 there is.

1:1 ratio, therefore 3.5 mole of MgCl2 is formed, which equals in grams, mole x molar mass, 3.5 x 59.5 = 208 grams

hope this is what your looking for!

we always start with an equation

Mg(OH)2 + 2HCl = MgCl2 + 2H2O

1 mole of the hydroxide r/w 2 mole sof the acid

Molar mass of Mg(OH)2 is 58.32 g/mol so moles of Mg(OH)2 in 203 g = 203 / 58.32

= 3.5 moles

this can react with 7.0 moles of HCl

Molar mass of HCl is 36.46 g/mol

we have 164 g of HCl or 164 / 36.46 = 4.5 moles which is less than the amount the hydroxide could react with so the HCl is the limiting reagent and forms

4.5 / 2 moles of the MgCl2 = 2.25 moles

Molar mass of MgCl2 is 95.21 g/mol

so mass of MgCl2 formed = 2.25 X 95.21 = 214.22 g

use the formulation pv = nRT, the place p is tension, v is quantity, n is the variety of moles of the gas, R is the gas consistent and T is the temperature in kelvin. resolve for V. each and everything different than "n" is given to you (considering the fact that its at rtp) to discover the variety of moles, evaluate that interior the reaction, for each 2 moles of zinc sulfide you react, you get 2 moles of sulfur dioxide. this suggests you get a million mole of product for each mole of reactants. meaning the variety of moles of the product is an identical because of the fact the variety of moles of the reactant. case in point, in case you reacted 10 moles of the zinc, you will get 10 moles of the sulfur. with the point to discover "n", all you would be able to desire to do is discover out how many moles of the zinc you had. zinc sulfide has an atomic mass of ninety seven. meaning there are ninety seven grams in a million mole. in case you have 9.7 grams, then you've a million/10ths of a mole of the the reactant, meaning you have a million/10 moles of the product. use a million/10 for "n".