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Chemistry?
A gas phase reaction has an activation energy of 123 kJ/mol, and the rate constant is 0.0800 min-1 at 45.0ºC. Find the rate constant when the temperature is 135.0ºC.
I keep getting 0.00000281 min.
1 Answer
- hcbiochemLv 75 days ago
Since you are raising the temperature, the rate constant should be larger. I use the equation:
ln (k2/k1) = Ea/R (1/T1-1/T2)
Temps must be in Kelvin and the Ea should be converted to J/mol.
ln (k2/0.0800) = 1.23X10^5 J/mol / 8.314 J/molK (1/318 - 1/408 K)
ln (k2/0.0800) = 1.23X10^5 J/mol / 8.314 J/molK (6.937X10^-4)
ln (k2/0.0800) = 10.2624
k2/0.0800 = 3^10.2624 = 28636
k2 - 2.29X10^3 min^-1
Hope this helps...
